-360+8x^2-32x=0

Solution for -360+8x^2-32x=0 equation:

-360+8x^2-32x=0

a = 8; b = -32; c = -360;
Δ = b2-4ac
Δ = -322-4·8·(-360)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-112}{2*8}=\frac{-80}{16}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+112}{2*8}=\frac{144}{16}
=9
$